Question

The electronegativities of $C,N,Si$ and $P$ are in the order of

• A. $P<Si<C<N$
• B. $Si<P<N<C$
• C. $Si<P<C<N$
• D. $P<Si<N<C$

Answer 1

Answer: (C)

Electronegativity increases as we more left to right in a period and decreases as we move down in the group.

(i) $C$ and $N$ belong to the same period. Hence $N$ has more electronegativity than carbon (C).

(ii) In the same way $P$ is more electronegative than Si

(iii) As Si is below the carbon is 14th group the electronegativity of carbons is more than of Si.