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Chemistry
The electronegativities of C, N, Si and P are in the order of
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Q. The electronegativities of $C, N, Si$ and $P$ are in the order of
KCET
KCET 2017
Classification of Elements and Periodicity in Properties
A
$P < Si < C < N$
12%
B
$Si < P < N < C$
16%
C
$Si < P < C < N$
58%
D
$P < Si < N < C$
14%
Solution:
Electronegativity increases as we more left to right in a period and decreases as we move down in the group.
(i) $C$ and $N$ belong to the same period. Hence $N$ has more electronegativity than carbon (C).
(ii) In the same way $P$ is more electronegative than Si
(iii) As Si is below the carbon is 14th group the electronegativity of carbons is more than of Si.