The electric potential at a certain distance from a point charge is 600 V and the electric field is 200 NC -1. The distance of the point charge (in metres) is

Question

The electric potential at a certain distance from a point charge is 600 V and the electric field is 200 NC -1. The distance of the point charge (in metres) is (A) 2 (B) 3 (C) 1 (D) 0

Tardigrade Admin · Accepted Answer

As electric field, E=(V/r) The distance of point charge, r=(V/E)=(600 V /200 NC -1) =3 m

Q. The electric potential at a certain distance from a point charge is $600 V$ and the electric field is $200 N C^{- 1}$ . The distance of the point charge (in metres) is

2

3

1

0

As electric field, $E = \frac{V}{r}$
The distance of point charge, $r = \frac{V}{E} = \frac{600 V}{200 N C ^{- 1}}$
$= 3 m$

Q. The electric potential at a certain distance from a point charge is 600V and the electric field is 200NC−1. The distance of the point charge (in metres) is

2

3

1

0

As electric field, E=rV​ The distance of point charge, r=EV​=200NC−1600V​ =3m

Q. The electric potential at a certain distance from a point charge is $600 V$ and the electric field is $200 N C^{- 1}$ . The distance of the point charge (in metres) is

As electric field, $E = \frac{V}{r}$
The distance of point charge, $r = \frac{V}{E} = \frac{600 V}{200 N C ^{- 1}}$
$= 3 m$