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Q. The electric potential at a certain distance from a point charge is $600\, V$ and the electric field is $200\, NC ^{-1}$. The distance of the point charge (in metres) is

Electrostatic Potential and Capacitance

Solution:

As electric field, $E=\frac{V}{r}$
The distance of point charge, $r=\frac{V}{E}=\frac{600\, V }{200\, NC ^{-1}}$
$=3\, m$