The electric flux from a cube of edge l is φ. If an edge of the cube is made 2 l and the charge enclosed is halved, its value will be

Question

The electric flux from a cube of edge l is φ. If an edge of the cube is made 2 l and the charge enclosed is halved, its value will be (A) 4 φ (B) 2 φ (C) φ / 2 (D) φ

Tardigrade Admin · Accepted Answer

φ=(q/ε0) (Independent of dimensions) New flux, φ prime=(φ/2)

Q. The electric flux from a cube of edge $l$ is $ϕ$ . If an edge of the cube is made $2 l$ and the charge enclosed is halved, its value will be

$4 ϕ$

$2 ϕ$

$ϕ /2$

$ϕ$

$ϕ = \frac{q}{ε _{0}}$ (Independent of dimensions)
New flux, $ϕ^{'} = \frac{ϕ}{2}$

Q. The electric flux from a cube of edge l is ϕ. If an edge of the cube is made 2l and the charge enclosed is halved, its value will be

4ϕ

2ϕ

ϕ/2

ϕ

ϕ=ε0​q​ (Independent of dimensions) New flux, ϕ′=2ϕ​

Q. The electric flux from a cube of edge $l$ is $ϕ$ . If an edge of the cube is made $2 l$ and the charge enclosed is halved, its value will be

$4 ϕ$

$2 ϕ$

$ϕ /2$

$ϕ$

$ϕ = \frac{q}{ε _{0}}$ (Independent of dimensions)
New flux, $ϕ^{'} = \frac{ϕ}{2}$