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Physics
The electric flux from a cube of edge l is φ. If an edge of the cube is made 2 l and the charge enclosed is halved, its value will be
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Q. The electric flux from a cube of edge $l$ is $\phi$. If an edge of the cube is made $2 l$ and the charge enclosed is halved, its value will be
Electric Charges and Fields
A
$4 \phi$
11%
B
$2 \phi$
22%
C
$\phi / 2$
47%
D
$\phi$
20%
Solution:
$\phi=\frac{q}{\varepsilon_{0}}$ (Independent of dimensions)
New flux, $\phi^{\prime}=\frac{\phi}{2}$