The electric field components in the given figures are Ex=α x1 / 2, Ey=Ez=0 in which α=800 N C -1 m -1 / 2 . The charge within the cube is if net flux through the cube is 1.05 N m 2 C -1( assume a =0.1 m )

Question

The electric field components in the given figures are Ex=α x1 / 2, Ey=Ez=0 in which α=800 N C -1 m -1 / 2 . The charge within the cube is if net flux through the cube is 1.05 N m 2 C -1( assume a =0.1 m ) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b1ed2f373fd3757b683c9eddc72d2739-.png" /> (A) 9.27 × 10-12 C (B) 9.27 × 1012 C (C) 6.97 × 10-12 C (D) 6.97 × 1012 C

Tardigrade Admin · Accepted Answer

By Gauss's law, φ=(q/ε0) or q=φ ε0 =1.05 × 8.854 × 10-12 C =9.27 × 10-12 C

Q. The electric field components in the given figures are $E_{x} = α x^{1/2}, E_{y} = E_{z} = 0$ in which $α = 800 N C^{- 1} m^{- 1/2} .$ The charge within the cube is if net flux through the cube is $1.05 N m^{2} C^{- 1} ($ assume $a = 0.1 m)$

$9.27 \times 1 0^{- 12} C$

$9.27 \times 1 0^{12} C$

$6.97 \times 1 0^{- 12} C$

$6.97 \times 1 0^{12} C$

By Gauss's law,
$ϕ = \frac{q}{ε _{0}}$
or $q = ϕ ε_{0}$
$= 1.05 \times 8.854 \times 1 0^{- 12} C$
$= 9.27 \times 1 0^{- 12} C$

Q. The electric field components in the given figures are Ex​=αx1/2,Ey​=Ez​=0 in which α=800NC−1m−1/2. The charge within the cube is if net flux through the cube is 1.05Nm2C−1( assume a=0.1m)

9.27×10−12C

9.27×1012C

6.97×10−12C

6.97×1012C