Question

The electric field components in the given figures are $E_{x}=\alpha x^{1 / 2}, E_{y}=E_{z}=0$ in which $\alpha=800 N C ^{-1} m ^{-1 / 2} .$ The charge within the cube is if net flux through the cube is $1.05 N m ^{2} C ^{-1}($ assume $a =0.1 m )$

• A. $9.27 \times 10^{-12} C$
• B. $9.27 \times 10^{12} C$
• C. $6.97 \times 10^{-12} C$
• D. $6.97 \times 10^{12} C$

Answer 1

Answer: (A)

By Gauss's law,
$\phi=\frac{q}{\varepsilon_{0}}$
or $q=\phi \varepsilon_{0}$
$=1.05 \times 8.854 \times 10^{-12} C$
$=9.27 \times 10^{-12} C$