Question

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
$E_x=E_o\sin (kz-\omega t)$
$B_y=B_0\sin (kz-\omega t)$
Then the correct relation between $E_0$ and $B_0$ is given by

• A. $E_0{B}_0=\omega k$
• B. $E_0=k{B}_0$
• C. $k{E}_0=\omega B_0$
• D. $\omega E_0=k{B}_0$

Answer 1

Answer: (C)

$C=\frac{\omega }{k}=\frac{E_0}{B_0}$