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Q. The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
$ E _x= E _{ o } \sin ( kz -\omega t )$
$ B _y= B _0 \sin ( kz -\omega t )$
Then the correct relation between $E _0$ and $B _0$ is given by

JEE MainJEE Main 2023Electromagnetic Waves

Solution:

$C =\frac{\omega}{ k }=\frac{ E _0}{ B _0}$