The elastic limit of brass is 379MPa . The minimum diameter of a brass rod if it is to support a 400N load without exceeding its elastic limit is:

Question

The elastic limit of brass is 379MPa . The minimum diameter of a brass rod if it is to support a 400N load without exceeding its elastic limit is: (A) 1.1mm (B) 0.90mm (C) 1.36mm (D) 1.16mm

Tardigrade Admin · Accepted Answer

Stress =(F/A)=(400/π (d2)4)=379× 106 (400 × 4/π × 379 × 106)=d2 d=1.159× 10- 3m d≈1.16mm

Q. The elastic limit of brass is $379 MP a$ . The minimum diameter of a brass rod if it is to support a $400 N$ load without exceeding its elastic limit is:

$1.1 mm$

$0.90 mm$

$1.36 mm$

$1.16 mm$

Stress $= \frac{F}{A} = \frac{400}{π \frac{d ^{2}}{4}} = 379 \times 1 0^{6}$
$\frac{400 \times 4}{π \times 379 \times 1 0 ^{6}} = d^{2}$
$d = 1.159 \times 1 0^{- 3} m$
$d \approx 1.16 mm$

Q. The elastic limit of brass is 379MPa . The minimum diameter of a brass rod if it is to support a 400N load without exceeding its elastic limit is:

1.1mm

0.90mm

1.36mm

1.16mm