Question

The efficiency of a reversible heat engine working between the temperature $100^{\circ }C$ and $0^{\circ }C$ is

• A. 82.6 %
• B. 28.6 %
• C. 6.28 %
• D. 26.8 %

Answer 1

Answer: (D)

$T_1=273+100=373$
$T_2=273+0=273K$
$\eta =1-\frac{T_2}{T_1}=\left(1-\frac{273}{373}\right)=\frac{100}{373}$
$\therefore \eta =\frac{100\times 100}{373}=26.8$%