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  4. The efficiency of a reversible heat engine working between the temperature 100° C and 0° C is

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Q. The efficiency of a reversible heat engine working between the temperature $100^\circ\,C$ and $0^\circ\,C$ is

Thermodynamics

Solution:

$T_1=273 + 100 = 373 $
$T_2= 273 + 0 = 273 K$
$\eta=1-\frac{T_2}{T_1}=\left(1-\frac{273}{373}\right)=\frac{100}{373}\,$
$\therefore \eta=\frac{100\times100}{373}=26.8$%