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Tardigrade
Question
Chemistry
The effective atomic number of Cr (atomic no. 24) in [Cr(NH3)6]Cl3 is
Q. The effective atomic number of
C
r
(atomic no.
24
) in
[
C
r
(
N
H
3
)
6
]
C
l
3
is
3657
184
Manipal
Manipal 2010
Coordination Compounds
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A
35
7%
B
27
14%
C
33
68%
D
36
11%
Solution:
Effective atomic number, EAN = number of electrons in
C
r
+
2
×
number of ligands
−
charge
=
24
+
2
×
6
−
3
=
33