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Q. The effective atomic number of $ Cr $ (atomic no. $24$) in $ [Cr(NH_3)_6]Cl_3 $ is

ManipalManipal 2010Coordination Compounds

Solution:

Effective atomic number, EAN = number of electrons in $ Cr+2\times $ number of ligands $ - $ charge
$ =24+2\times 6-3=33 $