Question

The edge length of the unit cell of $NaCl$ crystal lattice is $552pm$. If the ionic radius of sodium ion is $95pm$. What is the ionic radius of chloride ion?

• A. 181 pm
• B. 190 pm
• C. 2 76 pm
• D. 368 pm

Answer 1

Answer: (A)

The edge length of unit cell of $NaCl=552pm$
The ionic radius of sodium ion $=95pm$
The ionic radius of $C{l}^{-}$ion $=\frac{552}{2}-95$
$=276-95=181pm$