Thank you for reporting, we will resolve it shortly
Q.
The edge length of the unit cell of $NaCl$ crystal lattice is $552\, pm$. If the ionic radius of sodium ion is $95\, pm$. What is the ionic radius of chloride ion?
The Solid State
Solution:
The edge length of unit cell of $NaCl =552\, pm$
The ionic radius of sodium ion $=95 \,pm$
The ionic radius of $Cl ^{-}$ion $=\frac{552}{2}-95$
$=276-95=181 \,pm$