Question

The EAN of Ni in $[Ni(CN{)}_4{]}^{2-}$ is

• A. 34
• B. 35
• C. 36
• D. 28

Answer 1

Answer: (A)

Oxidation number of Ni in $[Ni(CN{)}_4{]}^{2-}$ is 2.
$\therefore$ EAN = Z-O .N . + 2$\times$ L
= 28 - 2 + 2 $\times$ 4 = 34.