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Q. The EAN of Ni in $[Ni(CN)_4]^{2-}$ is

Coordination Compounds

Solution:

Oxidation number of Ni in $[Ni(CN)_4]^{2-}$ is 2.
$\therefore $ EAN = Z-O .N . + 2$\times$ L
= 28 - 2 + 2 $\times$ 4 = 34.