The distance of closest approach of an α- particle fired towards a nucleus with momentum ' P ' is ' r '. What will be distance of closest approach when the momentum of particle α- is 2 P ?

Question

The distance of closest approach of an α- particle fired towards a nucleus with momentum ' P ' is ' r '. What will be distance of closest approach when the momentum of particle α- is 2 P ? (A) 2 r (B) 4 r (C) r / 2 (D) r / 4

Tardigrade Admin · Accepted Answer

(1/4 π ∈0) (2 z e2/r) =K ⋅ E=(P2/2 m)

Q. The distance of closest approach of an $α -$ particle fired towards a nucleus with momentum ' $P$ ' is ' $r$ '. What will be distance of closest approach when the momentum of particle $α -$ is $2 P$ ?

2 r

4 r

r / 2

r / 4

$\frac{1}{4 π \in _{0}} \frac{2 z e ^{2}}{r}$
$= K \cdot E = \frac{P ^{2}}{2 m}$

Q. The distance of closest approach of an α− particle fired towards a nucleus with momentum ' P ' is ' r '. What will be distance of closest approach when the momentum of particle α− is 2P ?

2 r

4 r

r / 2

r / 4

4π∈0​1​r2ze2​ =K⋅E=2mP2​

Q. The distance of closest approach of an $α -$ particle fired towards a nucleus with momentum ' $P$ ' is ' $r$ '. What will be distance of closest approach when the momentum of particle $α -$ is $2 P$ ?

$\frac{1}{4 π \in _{0}} \frac{2 z e ^{2}}{r}$
$= K \cdot E = \frac{P ^{2}}{2 m}$