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  4. The distance of closest approach of an α- particle fired towards a nucleus with momentum ' P ' is ' r '. What will be distance of closest approach when the momentum of particle α- is 2 P ?

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Q. The distance of closest approach of an $\alpha-$ particle fired towards a nucleus with momentum ' $P$ ' is ' $r$ '. What will be distance of closest approach when the momentum of particle $\alpha-$ is $2 P$ ?

Solution:

$\frac{1}{4 \pi\, \in_{0}} \frac{2 \,z e^{2}}{r} $
$=K \cdot E=\frac{P^{2}}{2\, m}$