The distance between the ends of wings of an aeroplane is 5 m. The aeroplane is moving with velocity of 200 km/sec in a magnetic field of 10 T. The emf induced across the ends of wings will be:

Question

The distance between the ends of wings of an aeroplane is 5 m. The aeroplane is moving with velocity of 200 km/sec in a magnetic field of 10 T. The emf induced across the ends of wings will be: (A)  107 volt (B) 10 volt (C)  106 volt (D) none of these

Tardigrade Admin · Accepted Answer

e=B v l ...(i) Here: B=10 T , v=200 km / sec =2 × 105 m / sec , l=5 m Putting given values is eq (i) ∴ e =10 × 2 × 105 × 5 =1 × 107 volt

Q. The distance between the ends of wings of an aeroplane is $5 m$ . The aeroplane is moving with velocity of $200 km / sec$ in a magnetic field of $10 T .$ The emf induced across the ends of wings will be:

$1 0^{7}$ volt

$10$ volt

$1 0^{6}$ volt

none of these

$e = B v l ... (i)$
Here $: B = 10 T, v = 200 km / sec$
$= 2 \times 1 0^{5} m / sec, l = 5 m$
Putting given values is eq (i)
$∴ e = 10 \times 2 \times 1 0^{5} \times 5$
$= 1 \times 1 0^{7}$ volt

Q. The distance between the ends of wings of an aeroplane is 5m. The aeroplane is moving with velocity of 200km/sec in a magnetic field of 10T. The emf induced across the ends of wings will be:

107 volt

10 volt

106 volt