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Q. The distance between the ends of wings of an aeroplane is $5\, m$. The aeroplane is moving with velocity of $200\, km/sec$ in a magnetic field of $10\, T.$ The emf induced across the ends of wings will be:

Rajasthan PMTRajasthan PMT 2004Electromagnetic Induction

Solution:

$e=B v l\,\,\,\,...(i)$
Here $: B=10\, T , v=200 \,km / sec$
$=2 \times 10^{5}\, m / sec , l=5\, m$
Putting given values is eq (i)
$\therefore e =10 \times 2 \times 10^{5} \times 5 $
$=1 \times 10^{7}$ volt