The displacement time graph of a moving particle is shown below The instantaneous velocity of the particle is negative at the point

Question

The displacement time graph of a moving particle is shown below <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-scodnek6d0ad.png" /> The instantaneous velocity of the particle is negative at the point (A)  textC (B)  textE (C)  textD (D)  textF

Tardigrade Admin · Accepted Answer

At E, the slope of the curve is negative, i.e. for a displacement-time graph the slope represents the velocity and at E, the velocity is - textv texte as the slope is - textv texte .

Q. The displacement time graph of a moving particle is shown below

The instantaneous velocity of the particle is negative at the point

$C$

$E$

$D$

$F$

At $E,$ the slope of the curve is negative, i.e. for a displacement-time graph the slope represents the velocity and at $E,$ the velocity is $- v e$ as the slope is $- v e$ .

Q. The displacement time graph of a moving particle is shown below The instantaneous velocity of the particle is negative at the point

C

E

D

F

At E, the slope of the curve is negative, i.e. for a displacement-time graph the slope represents the velocity and at E, the velocity is −ve as the slope is −ve .

Q. The displacement time graph of a moving particle is shown below

The instantaneous velocity of the particle is negative at the point

$C$

$E$

$D$

$F$

At $E,$ the slope of the curve is negative, i.e. for a displacement-time graph the slope represents the velocity and at $E,$ the velocity is $- v e$ as the slope is $- v e$ .