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Q. The displacement time graph of a moving particle is shown below

Question

The instantaneous velocity of the particle is negative at the point

NTA AbhyasNTA Abhyas 2020Motion in a Straight Line

Solution:

At $E,$ the slope of the curve is negative, i.e. for a displacement-time graph the slope represents the velocity and at $E,$ the velocity is $- \text{v} \text{e}$ as the slope is $- \text{v} \text{e}$ .