The displacement (s) - velocity (.v.) graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is

Question

The displacement (s) - velocity (.v.) graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

Since initial velocity is zero, v2=2ass=(v2/2 a) It is similar to graph of parabola given by y=x2 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-zsojvkqhjlojjddh.jpg" />

Q. The displacement $(s)$ - velocity $(v)$ graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is

Since initial velocity is zero,
$v^{2} = 2 a ss = \frac{v ^{2}}{2 a}$
It is similar to graph of parabola given by $y = x^{2}$

Q. The displacement (s) - velocity (v) graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is

Since initial velocity is zero, v2=2ass=2av2​ It is similar to graph of parabola given by y=x2

Q. The displacement $(s)$ - velocity $(v)$ graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is

Since initial velocity is zero,
$v^{2} = 2 a ss = \frac{v ^{2}}{2 a}$
It is similar to graph of parabola given by $y = x^{2}$