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  4. The displacement (s) - velocity (.v.) graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is

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Q. The displacement $\left(s\right)$ - velocity $\left(\right.v\left.\right)$ graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is

NTA AbhyasNTA Abhyas 2022

Solution:

Since initial velocity is zero,
$v^{2}=2ass=\frac{v^{2}}{2 a}$
It is similar to graph of parabola given by $y=x^{2}$
Solution