The displacement of a particle executing SHM is given by y = 0.25sin200t cm. The maximum speed of the particle is

Question

The displacement of a particle executing SHM is given by y = 0.25sin200t cm. The maximum speed of the particle is (A) 200 cm s-1 (B) 100 cm s-1 (C) 50 cm s-1 (D) 5.25 cm s-1

Tardigrade Admin · Accepted Answer

Given: y = 0.25 sin 200t Speed =(dy/dt) = 0.25 × 200 cos 200t Max speed = 0.25 Ã 200 = 50 cm s-1

Q. The displacement of a particle executing SHM is given by y = 0.25sin200t cm. The maximum speed of the particle is

200 cm s^-1

100 cm s^-1

50 cm s^-1

5.25 cm s^-1

Given : y = 0.25 sin 200t
Speed = $\frac{d y}{d t}$ = 0.25 $\times$ 200 cos 200t
Max speed = 0.25 $\times$ 200 = 50 cm s $^{- 1}$

Q. The displacement of a particle executing SHM is given by y = 0.25sin200t cm. The maximum speed of the particle is

200 cm s-1

100 cm s-1

50 cm s-1

5.25 cm s-1

Given : y = 0.25 sin 200t Speed =dtdy​ = 0.25 × 200 cos 200t Max speed = 0.25 × 200 = 50 cm s−1

200 cm s^-1

100 cm s^-1

50 cm s^-1

5.25 cm s^-1

Given : y = 0.25 sin 200t
Speed = $\frac{d y}{d t}$ = 0.25 $\times$ 200 cos 200t
Max speed = 0.25 $\times$ 200 = 50 cm s $^{- 1}$