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  4. The displacement of a particle executing SHM is given by y = 0.25sin200t cm. The maximum speed of the particle is

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Q. The displacement of a particle executing SHM is given by y = 0.25sin200t cm. The maximum speed of the particle is

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Solution:

Given : y = 0.25 sin 200t
Speed =$\frac{dy}{dt}$ = 0.25 $\times$ 200 cos 200t
Max speed = 0.25 $×$ 200 = 50 cm s$^{-1}$