The displacement of a particle executing SHM is given by X=3 sin [2 π t+(π/4)] where ' x ' is in meters and ' t ' is in seconds. The amplitude and maximum speed of the particle is

Question

The displacement of a particle executing SHM is given by X=3 sin [2 π t+(π/4)] where ' x ' is in meters and ' t ' is in seconds. The amplitude and maximum speed of the particle is (A) 3 m , 6 π ms -1 (B) 3 m , 8 π ms -1 (C) 3 m , 2 π ms -1 (D) 3 m , 4 π ms -1

Tardigrade Admin · Accepted Answer

A=3 m V max =A ω=3 × 2 π=6 π

Q. The displacement of a particle executing SHM is given by $X = 3 sin [2 π t + \frac{π}{4}]$ where ' $x$ ' is in meters and ' $t$ ' is in seconds. The amplitude and maximum speed of the particle is

$3 m, 6 π m s^{- 1}$

$3 m, 8 π m s^{- 1}$

$3 m, 2 π m s^{- 1}$

$3 m, 4 π m s^{- 1}$

$A = 3 m$
$V_{m a x} = A ω = 3 \times 2 π = 6 π$

Q. The displacement of a particle executing SHM is given by X=3sin[2πt+4π​] where ' x ' is in meters and ' t ' is in seconds. The amplitude and maximum speed of the particle is

3m,6πms−1

3m,8πms−1

3m,2πms−1

3m,4πms−1