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Q. The displacement of a particle executing SHM is given by $X=3 \sin \left[2 \pi t+\frac{\pi}{4}\right]$ where ' $x$ ' is in meters and ' $t$ ' is in seconds. The amplitude and maximum speed of the particle is

KCETKCET 2022Oscillations

Solution:

$A=3 \,m$
$V_{\max }=A \omega=3 \times 2 \pi=6 \pi$