Question

The displacement of a particle executing SHM is given by $X=3 \sin \left[2 \pi t+\frac{\pi}{4}\right]$ where ' $x$ ' is in meters and ' $t$ ' is in seconds. The amplitude and maximum speed of the particle is

• A. $3 \,m , 6 \pi \,ms ^{-1}$
• B. $3 \,m , 8 \pi \,ms ^{-1}$
• C. $3 \,m , 2 \pi \,ms ^{-1}$
• D. $3\, m , 4 \pi \,ms ^{-1}$

Answer 1

Answer: (A)

$A=3 \,m$
$V_{\max }=A \omega=3 \times 2 \pi=6 \pi$