The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position (x/3) (a/π), (x/3) (a/π) where x is . (Round off to the Nearest Integer) [a is an area as shown in the figure]

Question

The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position (x/3) (a/π), (x/3) (a/π) where x is . (Round off to the Nearest Integer) [a is an area as shown in the figure] <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6cb0a9b12b3d0d5f52e8557fcce888b9-.png" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

C.O.M of quarter disc is at (4 a/3 π), (4 a/3 π) =4

Q. The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position 3x​πa​,3x​πa​ where x is ________. (Round off to the Nearest Integer) [a is an area as shown in the figure]

C.O.M of quarter disc is at 3π4a​,3π4a​ =4

C.O.M of quarter disc is at $\frac{4 a}{3 π}, \frac{4 a}{3 π}$
$= 4$