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  4. The disc of mass M with uniform surface mass density σ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at the position (x/3) (a/π), (x/3) (a/π) where x is . (Round off to the Nearest Integer) [a is an area as shown in the figure] <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/6cb0a9b12b3d0d5f52e8557fcce888b9-.png />

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Q. The disc of mass $M$ with uniform surface mass density $\sigma$ is shown in the figure. The centre of mass of the quarter disc (the shaded area) is at
the position $\frac{x}{3} \frac{a}{\pi}, \frac{x}{3} \frac{a}{\pi}$ where $x$ is ________.
(Round off to the Nearest Integer) [a is an area as shown in the figure]
image

JEE MainJEE Main 2021System of Particles and Rotational Motion

Solution:

C.O.M of quarter disc is at $\frac{4 a}{3 \pi}, \frac{4 a}{3 \pi}$
$=4$