The dimensions of Planck constant equals to that of

Question

The dimensions of Planck constant equals to that of (A) energy (B) momentum (C) angular momentum (D) power

Tardigrade Admin · Accepted Answer

Dimensions of Planck constant h=( textEnergy/ textFrequency) =([ML2T-2]/[T-1])=[ML2T-1] Dimensions of angular momentum L = Moment of inertia I × Angular velocity ω =[ML2][T-1]=[ML2T-1]

Q. The dimensions of Planck constant equals to that of

energy

momentum

angular momentum

power

Dimensions of Planck constant $h = \frac{Energy}{Frequency}$
$= \frac{[ M L ^{2} T ^{- 2} ]}{[ T ^{- 1} ]} = [M L^{2} T^{- 1}]$
Dimensions of angular momentum $L$
= Moment of inertia $I \times$ Angular velocity $ω$
$= [M L^{2}] [T^{- 1}] = [M L^{2} T^{- 1}]$

Q. The dimensions of Planck constant equals to that of

energy

momentum

angular momentum

power

Dimensions of Planck constant h=FrequencyEnergy​ =[T−1][ML2T−2]​=[ML2T−1] Dimensions of angular momentum L = Moment of inertia I× Angular velocity ω =[ML2][T−1]=[ML2T−1]

Dimensions of Planck constant $h = \frac{Energy}{Frequency}$
$= \frac{[ M L ^{2} T ^{- 2} ]}{[ T ^{- 1} ]} = [M L^{2} T^{- 1}]$
Dimensions of angular momentum $L$
= Moment of inertia $I \times$ Angular velocity $ω$
$= [M L^{2}] [T^{- 1}] = [M L^{2} T^{- 1}]$