Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The dimensions of Planck constant equals to that of

AIPMTAIPMT 2001Physical World, Units and Measurements

Solution:

Dimensions of Planck constant $h=\frac{\text{Energy}}{\text{Frequency}}$
$=\frac{[ML^2T^{-2}]}{[T^{-1}]}=[ML^2T^{-1}]$
Dimensions of angular momentum $L$
= Moment of inertia $I \times$ Angular velocity $\omega$
$=[ML^2][T^{-1}]=[ML^2T^{-1}]$