Question

The dimensions of kinetic energy is

• A. $[M^2{L}^{2}T]$
• B. $[M{L}^{2}T]$
• C. $[M{L}^2{T}^{-2}]$
• D. $[M{L}^2{T}^{-1}]$

Answer 1

Answer: (C)

$KE=\frac{1}{2}m{v}^2$
$\therefore [KE]=[M]{\left[L{T}^{-1}\right]}^2$
$=\left[M{L}^2{T}^{-2}\right]$