1. Tardigrade
  2. Question
  3. Physics
  4. The dimensions of kinetic energy is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The dimensions of kinetic energy is

WBJEEWBJEE 2007

Solution:

$K E=\frac{1}{2} m v^{2}$
$\therefore [K E]=[M]\left[L T^{-1}\right]^{2}$
$=\left[M L^{2} T^{-2}\right]$