The dimensions of energy density of magnetic field (1/2) (B2/μ0), where B is magnetic field and μ0 is the magnetic permeability of vacuum, is

Question

The dimensions of energy density of magnetic field (1/2) (B2/μ0), where B is magnetic field and μ0 is the magnetic permeability of vacuum, is (A) [ MLT -2] (B) [ ML 2 T -1] (C) [ ML 2 T -2] (D) [ ML -1 T -2]

Tardigrade Admin · Accepted Answer

Energy density of magnetic field. (B2/2 μ0)=( text Energy / text Volume )=(M L2 T-2/L3)=[M L-1 T-2]

Q. The dimensions of energy density of magnetic field $\frac{1}{2} \frac{B ^{2}}{μ _{0}}$ , where $B$ is magnetic field and $μ_{0}$ is the magnetic permeability of vacuum, is

$[M L T^{- 2}]$

$[M L^{2} T^{- 1}]$

$[M L^{2} T^{- 2}]$

$[M L^{- 1} T^{- 2}]$

Energy density of magnetic field.
$\frac{B ^{2}}{2 μ _{0}} = \frac{Energy}{Volume} = \frac{M L ^{2} T ^{- 2}}{L ^{3}} = [M L^{- 1} T^{- 2}]$

Q. The dimensions of energy density of magnetic field 21​μ0​B2​, where B is magnetic field and μ0​ is the magnetic permeability of vacuum, is

[MLT−2]

[ML2T−1]

[ML2T−2]

[ML−1T−2]