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Q. The dimensions of energy density of magnetic field $\frac{1}{2} \frac{B^2}{\mu_0}$, where $B$ is magnetic field and $\mu_0$ is the magnetic permeability of vacuum, is

Physical World, Units and Measurements

Solution:

Energy density of magnetic field.
$\frac{B^2}{2 \mu_0}=\frac{\text { Energy }}{\text { Volume }}=\frac{M L^2 T^{-2}}{L^3}=\left[M L^{-1} T^{-2}\right]$