The dimensions of emf in MKS is:

Question

The dimensions of emf in MKS is: (A)  mathrmML-1 mathrm~T-2 mathrmQ-2 (B)  mathrmML2 mathrm~T-2 mathrmQ-2 (C)  mathrmMLT-2 mathrmQ-1 (D) M L2 T-2 Q-1

Tardigrade Admin · Accepted Answer

beginaligned text mathrme= mathrmL ( mathrmdi/ mathrmdt) &[ mathrme]=[ mathrmML2 mathrm~T-2 mathrm~A-2][( mathrmA/ mathrmT)]=[( mathrmML2 mathrm~T-2/ mathrmAT)] [ mathrmML2 mathrm~T-2 mathrmQ-1] endaligned

Q. The dimensions of emf in MKS is:

$ML^{- 1} T^{- 2} Q^{- 2}$

$ML^{2} T^{- 2} Q^{- 2}$

$MLT^{- 2} Q^{- 1}$

$M L^{2} T^{- 2} Q^{- 1}$

$e = L \frac{di}{dt} [e] = [ML^{2} T^{- 2} A^{- 2}] [\frac{A}{T}] = [\frac{ML ^{2} T ^{- 2}}{AT}] [ML^{2} T^{- 2} Q^{- 1}]$

Q. The dimensions of emf in MKS is:

ML−1 T−2Q−2

ML2 T−2Q−2

MLT−2Q−1

ML2T−2Q−1

​ e=Ldtdi​[e]=[ML2 T−2 A−2][TA​]=[ATML2 T−2​][ML2 T−2Q−1]​

$ML^{- 1} T^{- 2} Q^{- 2}$

$ML^{2} T^{- 2} Q^{- 2}$

$MLT^{- 2} Q^{- 1}$

$M L^{2} T^{- 2} Q^{- 1}$

$e = L \frac{di}{dt} [e] = [ML^{2} T^{- 2} A^{- 2}] [\frac{A}{T}] = [\frac{ML ^{2} T ^{- 2}}{AT}] [ML^{2} T^{- 2} Q^{- 1}]$