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  4. The dimensions of emf in MKS is:

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Q. The dimensions of emf in MKS is:

Physical World, Units and Measurements

Solution:

$ \begin{aligned} &\text { } \mathrm{e}=\mathrm{L} \frac{\mathrm{di}}{\mathrm{dt}}\\ &[\mathrm{e}]=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right]\left[\frac{\mathrm{A}}{\mathrm{T}}\right]=\left[\frac{\mathrm{ML}^{2} \mathrm{~T}^{-2}}{\mathrm{AT}}\right] \left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{Q}^{-1}\right] \end{aligned}$