Question

The dimension ${\text{(velocity)}}^2/$ radius are the same of that of

• A. Planck's constant
• B. gravitational constant
• C. dielectric constant
• D. None of these

Answer 1

Answer: (D)

Dimensions formula of (velocity ${)}^2/$ radius
$=\frac{{\left[M^{0}L{T}^{-1}\right]}^2}{\left[M^{0}L{T}^0\right]}=\left[L{T}^{-2}\right]$
Thus, it has the dimensions of acceleration