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Q. The dimension $ \text{(velocity)}^{2}/$ radius are the same of that of

ManipalManipal 2014

Solution:

Dimensions formula of (velocity $)^{2} /$ radius
$=\frac{\left[ M ^{0} LT ^{-1}\right]^{2}}{\left[ M ^{0} LT ^{0}\right]}=\left[ LT ^{-2}\right]$
Thus, it has the dimensions of acceleration