The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is:

Question

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is: (A) Ni 2+ (B) Fe 2+ (C) Co 2+ (D) Mn 2+

Tardigrade Admin · Accepted Answer

Metal ion No. unpaired electrons Difference in the unpaired electrons <thHigh spin <thLow spin Ni2+(3d8) 2 2 0 Mn2+(3d5) 5 1 4 Fe(3d6) 4 0 4 Co2+(3d7) 3 1 2

Metal ion	No. unpaired electrons		Difference in the unpaired electrons

$N i^{2 +} (3 d^{8})$	2	2	0
$M n^{2 +} (3 d^{5})$	5	1	4
$F e (3 d^{6})$	4	0	4
$C o^{2 +} (3 d^{7})$	3	1	2

Q. The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is:

$N i^{2 +}$

$F e^{2 +}$

$C o^{2 +}$

$M n^{2 +}$

Metal ion No. unpaired electrons Difference in the unpaired electrons

$N i^{2 +} (3 d^{8})$ 2 2 0

$M n^{2 +} (3 d^{5})$ 5 1 4

$F e (3 d^{6})$ 4 0 4

$C o^{2 +} (3 d^{7})$ 3 1 2

Q. The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is:

Ni2+

Fe2+

Co2+

Mn2+

Metal ion No. unpaired electrons Difference in the unpaired electrons Ni2+(3d8) 2 2 0 Mn2+(3d5) 5 1 4 Fe(3d6) 4 0 4 Co2+(3d7) 3 1 2

$N i^{2 +}$

$F e^{2 +}$

$C o^{2 +}$

$M n^{2 +}$

Metal ion No. unpaired electrons Difference in the unpaired electrons

$N i^{2 +} (3 d^{8})$ 2 2 0

$M n^{2 +} (3 d^{5})$ 5 1 4

$F e (3 d^{6})$ 4 0 4

$C o^{2 +} (3 d^{7})$ 3 1 2