Q. The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is:
BITSATBITSAT 2021
Solution:
Metal ion
No. unpaired electrons
Difference in the unpaired electrons
$Ni^{2+}(3d^8)$
2
2
0
$Mn^{2+}(3d^5)$
5
1
4
$Fe(3d^6)$
4
0
4
$Co^{2+}(3d^7)$
3
1
2
| Metal ion | No. unpaired electrons | Difference in the unpaired electrons | |
|---|---|---|---|
| $Ni^{2+}(3d^8)$ | 2 | 2 | 0 |
| $Mn^{2+}(3d^5)$ | 5 | 1 | 4 |
| $Fe(3d^6)$ | 4 | 0 | 4 |
| $Co^{2+}(3d^7)$ | 3 | 1 | 2 |