The diameter of objective of a telescope is 1m. Its resolving limit for the light of wavelength 4538 mathringA, will be

Question

The diameter of objective of a telescope is 1m. Its resolving limit for the light of wavelength 4538 mathringA, will be (A)  5.54× 10-7rad  (B)  2.54× 10-4rad  (C)  6.54× 10-7rad  (D) None of the above

Tardigrade Admin · Accepted Answer

Resolving limit dθ =(1.22λ /a) =(1.22× 4538× 10-10/1) =5.54× 10-7rad

Q. The diameter of objective of a telescope is 1m. Its resolving limit for the light of wavelength $4538 \overset{˚}{A},$ will be

$5.54 \times 10^{- 7} r a d$

$2.54 \times 10^{- 4} r a d$

$6.54 \times 10^{- 7} r a d$

None of the above

Resolving limit
$d θ = \frac{1.22 λ}{a}$
$= \frac{1.22 \times 4538 \times 10 ^{- 10}}{1}$
$= 5.54 \times 10^{- 7} r a d$

Q. The diameter of objective of a telescope is 1m. Its resolving limit for the light of wavelength 4538A˚, will be

5.54×10−7rad

2.54×10−4rad

6.54×10−7rad