Question

The diameter of objective of a telescope is 1m. Its resolving limit for the light of wavelength $ 4538 \,\mathring{A}, $ will be

• A. $ 5.54\times {{10}^{-7}}rad $
• B. $ 2.54\times {{10}^{-4}}rad $
• C. $ 6.54\times {{10}^{-7}}rad $
• D. None of the above

Answer 1

Answer: (A)

Resolving limit
$ d\theta =\frac{1.22\lambda }{a} $
$ =\frac{1.22\times 4538\times {{10}^{-10}}}{1} $
$ =5.54\times {{10}^{-7}}rad $