Question

The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc. An iceberg of volume V is floating in sea water. The fraction of iceberg above water level is

• A. $1/11$
• B. $2/11$
• C. $3/11$
• D. $4/11$

Answer 1

Answer: (B)

: Volume of iceberg = V Density of iceberg $=0.9g/cc$ $\therefore$ Mass of iceberg $=V\times 0.9$ gram Let the volume above water level in sea $=v$ $\therefore$ Volume of iceberg immersed $=(V-v)$ $\therefore$ Volume ofseawater displaced $=(V-v)$ $\therefore$ ass of seawater displaced $=(V-v)1.1$ Since Weight of floating body = Weight of sea water displaced $\therefore$ $V\times 0.9\times g=(V-v)\times 1.1\times g$ or $0.9V=1.1V-1.1v$ or $1.1v=1.1V-0.9V$ or $\frac{v}{V}=\frac{0.2}{1.1}=\frac{2}{11}$