1. Tardigrade
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  3. Physics
  4. The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc. An iceberg of volume V is floating in sea water. The fraction of iceberg above water level is

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Q. The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc. An iceberg of volume V is floating in sea water. The fraction of iceberg above water level is

AMUAMU 1996

Solution:

: Volume of iceberg = V Density of iceberg $ =0.9\text{ }g/cc $ $ \therefore $ Mass of iceberg $ =V\times 0.9 $ gram Let the volume above water level in sea $ =v $ $ \therefore $ Volume of iceberg immersed $ =(V-v) $ $ \therefore $ Volume ofseawater displaced $ =(V-v) $ $ \therefore $ ass of seawater displaced $ =(V-v)1.1 $ Since Weight of floating body = Weight of sea water displaced $ \therefore $ $ V\times 0.9\times g=(V-v)\times 1.1\times g $ or $ 0.9V=1.1V-1.1v $ or $ 1.1v=1.1V-0.9V $ or $ \frac{v}{V}=\frac{0.2}{1.1}=\frac{2}{11} $