Question

The density (in $gm{L}^{-1}$) of a $3.60M$ sulphuric acid solution that is $29\%H_{2}S{O}_4$ (Molar mass $=98gmo{l}^{-1}$) by mass will be

• A. $1.64$
• B. $1.88$
• C. $1.22$
• D. $1.45$

Answer 1

Answer: (C)

Let the density of solution be $‘d’$
Molarity of solution given $=3.6$
i.e. 1 litre of solution contains 3.6 moles of $H_{2}S{O}_4$
or 1 litre of solution contains $3.6\times 98gms$ of $H_{2}S{O}_4$
Since, the solution is 29% by mass.
100 gm solution contains 29 gm $H_{2}S{O}_4$
$\frac{100}{d}ml$ solution contains $29gm$ of $H_{2}S{O}_4$
1000 ml solution contains $3.6\times 98gm$ of $H_{2}S{O}_4$
$\therefore 3.6\times 9.8=\frac{29\times d}{100}\times 1000$
$d=1.22$
Hence, (3) is correct.